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c++转换python返回的字符串

码农不了一点:

已经解决了，结果是python中的中文出现导致编码问题，只要将最终输出转换成utf-8编码输出就行了，参考的下面的文章

https://www.cnblogs.com/muchengnanfeng/p/9590404.html

c++转换python返回的字符串

码农不了一点:

[code=python]

def CityInquire(cityname):

city = unicode(cityname,'utf-8')

filename = "AMap_adcode_citycode_20210406.xlsx"

date = pd.read_excel(filename,header=0,index_col=0,encoding="utf-8")

adcode = date.loc[city,'adcode']

return int(adcode)

def GetDate(adcode):

mkey = '53e38fe6e4a9d29719c6210ad1295a'

mcity = adcode

url = "https://restapi.amap.com/v3/weather/weatherInfo?key={}&city={}".format(mkey,mcity)

response = requests.get(url)

if response.status_code==200:

date = json.loads(response.text)

ls = date['lives'][0]

city = ls['city']

temperature = ls['temperature_float']

humidity = ls['humidity_float']

info = "city:"+city+" temperature:"+temperature+" humidity:"+humidity

return info

else:

return 0

def main(cityname):

adcode = CityInquire(cityname)

info = GetDate(adcode)

print(info)

return info

[/code]

c++转换python返回的字符串

码农不了一点:

你好，我刚好遇到类似的问题，能否帮我看看呢？

[code=plain]

pi@ubuntu:~/Project$ ./a

ok

city:北京市 temperature:5.0 humidity:51.0

Exception UnicodeEncodeError: UnicodeEncodeError('ascii', u'city:\u5317\u4eac\u5e02 temperature:5.0 humidity:51.0', 5, 8, 'ordinal not in range(128)') in ignored

[/code]

我也觉得可能是编码问题，下面是C语言代码，功能就是向一个python函数传参并且接受返回的值，从上述结果来看已经是成功被调用而且传参也成功了，不过就是在接受返回参数的时候报错了。下面是具体的C程序：

[code=csharp]

char *getstr = "北京市";

char *filename = "WF";

//初始化python解释器

Py_Initialize();

if(!Py_IsInitialized()){

printf("Initialize failed!\n");

return 0;

}

//导入当前路径

PyRun_SimpleString("import sys");

PyRun_SimpleString("sys.path.append('./')");

PyObject *pmodule = PyImport_ImportModule(filename);

if(!pmodule){

printf("can't find %s\n",filename);

return 0;

}

printf("ok\n");

PyObject *pfunc = PyObject_GetAttrString(pmodule,"main");

//PyObject *pargs = Py_B

[/code]

补充一下，我还觉得可能是python返回参数编码的问题，因为有中文所以我将这个默认编码改成了utf-8。下面是具体的python程序